3 Ancient Greek Mathematics
3.1 Overview of Ancient Greek Civilization & Early Philosophy
Greek civilization dates from around 800 BC, centered between the Adriatic sea to the west and the
Aegean to the east. The ancient Greeks had a decentralized political culture consisting of mostly
independent city-states connected by trade. By 500 BC, much of modern Greece, the Aegean islands,
and southern Italy were part of a decentralized cultural empire. Accomplished sea-farers, the Greeks
extended their reach, building and capturing city-states/outposts round the northern and eastern
coasts of the Mediterranean, from Iberia round the Black Sea and Anatolia (western Turkey) to Egypt.
Philip of Macedon ‘unified’ the Greek peninsula just before his death in 336 BC. His son, Alexander
the Great, led a massive campaign conquering Persia, Egypt, Babylon, and western India before his
own death in Babylon in 323 BC. Alexander left provincial governors to manage captured territories;
some of these structures endured for centuries (e.g., Egypt’s Ptolemaic dynasty), while others were
overthrown after only a few years (e.g., parts of India). While Alexander’s conquests did not produce
a long-lasting centralized Greek empire, they were effective at expanding the reach of Greek cultural
practices and philosophy and brought external ideas into the Greek tradition.
The core part of Greek territory (map below) was absorbed by the Roman empire around 146 BC.
In line with typical Roman practice, local culture was left largely intact and scholarship continued
under Roman rule.
6
Greek culture and learning was central to the later Byzantine (eastern Roman)
empire (centered on Byzantium/Constantinople/Istanbul). Constantinople was eventually captured
by the Islamic Ottomans in 1453. While Islamic scholarship was itself significantly influenced by the
ancient Greeks, one result of the fall of Constantinople was the exodus of several scholars to Rome,
helping to fuel the European Renaissance.
Greek Territory c. 500 BC
Greek mathematics is part of a much wider development of science and philosophy encompassing
a change of emphasis from practicality to abstraction. One reason for this was the Greek blending
6
As long as a conquered people accepted Roman governors and paid taxes, they were accepted as Roman citizens. Of
course, if there was resistance. . .
15
of religion/mysticism with natural philosophy: philosophers wished to describe the natural world
while preserving the idea of perfection/logic in the gods’ design.
Early Greek inquiry into natural phenomena was encouraged through the personification of nature
(e.g., sky = man, earth = woman). By 600 BC, philosophers were attempting to describe such phenom-
ena in terms of natural predictable causes and structures. For example, some viewed matter as being
comprised of the ‘four elements’ (fire, earth, water, air); combined in the correct proportions. . . While
the system was seen as divinely-designed, reliance on the whims of the gods was discouraged.
While the Greeks certainly used mathematics for practical purposes, philosophers idealized logic and
were unhappy with approximations. This led to the development of axiomatics, theorems and proof,
concepts for which there is scant pre-Greek evidence. Indeed ancient Greek is the source of three
words of critical importance:
Mathematics comes from mathematos αθήµατoς), meaning knowledge or learning; the term covered
essentially anything that might be taught in Greek schools.
Geometry literally means earth-measure.
Gi (γη) dates from pre-5
th
century BC, meaning land, earth or soil. Capitalized (Γη) it could refer
to the Earth (as a goddess).
Metron έτρoν) was a weight or measure, a dimension (length, width, etc.), or the metre (rhythm)
in music.
Theorem comes from theoreo (θεώρέω), meaning ‘I contemplate,’ or ‘consider.’ In a mathematical
context this become theorema (θεώρηµα), a proposition to be proved.
Ancient Greece had several schools, mostly private and open only to men. Typically arithmetic was
taught until age 14, followed by geometry and astronomy until age 18. The most famous scholars of
ancient Greece were the Athenian trio of Socrates, Plato and Aristotle
7
whose writings became central
to the Western/Islamic philosophical tradition. Plato’s Academy in Athens was a model for centuries
of schooling, the centrality of geometry to the curriculum evidenced by the famous inscription above
the entryway: “Let none ignorant of geometry enter here.”
Enumeration
The ancient Greeks had two primary forms of enumeration, both dating from around 800–500 BC.
In Attic Greek (Attica = Athens) strokes were used for 1–4, while larger numerals used the first letter
of the words for 5, 10, 100, 1000 and 10000. For example,
Πεντε (pente) is Greek for five, whence Π denoted the number 5.
Δεκα (deca) means ten, so Δ represented 10.
Η (hekaton), X (khilias) and M (myrion/myriad) denoted 100, 1000 and 10000 respectively.
Combinations produced larger numbers, similar to Roman numerals, e.g., ΧΗΗΠ|| = 1207.
7
Each taught his successor; the birth of Socrates to the death of Aristotle covered 470–322 BC.
16
Ionic Greek (Ionia = mid Anatolian coast) numerals used the Greek al-
phabet, an approach they possibly copied from the Egyptian hieratic
method. Larger numbers used a left subscript mark (e.g., comma) to
denote thousands and/or M (with superscripts) for 10000, as in Attic
Greek. For example,
35298 = ,λ,εσϟη =
γ
M,εσϟη
The ancient Greek alphabet included three archaic symbols ϛ, ϟ, ϡ
(stigma, qoppa, sampi), with which you’re likely unfamiliar.
1 α 10 ι 100 ρ
2 β 20 κ 200 σ
3 γ 30 λ 300 τ
4 δ 40 µ 400 υ
5 ε 50 ν 500 ϕ
6 ϛ 60 ξ 600 χ
7 ζ 70 o 700 ψ
8 η 80 π 800 ω
9 θ 90 ϟ 900 ϡ
Eventually a bar was placed over numbers to distinguish them from words (e.g. ξθ = 89). Modern
practice is to place a keraia (similar to an apostrophe) at the end of a number: thus 35298 = ͵λ͵εσϟηʹ.
The Greeks also used Egyptian fractions, denoting reciprocals with an accent over the symbol: e.g.,
´
θ =
1
9
. The use of Egyptian fractions persisted in Europe well into the middle ages.
Both the Attic and Ionic systems were fine for record-keeping but terrible for calculations! Later
Greek mathematicians adapted the Babylonian sexagesimal system for calculation purposes, helping
cement its modern use of in astronomy, navigation and time-keeping.
Exercises 3.1. 1. State the number 1789 in both Attic and Ionic notation.
2. Represent
8
9
as a sum of distinct unit fractions (Egyptian style). Express the result in (Ionic)
Greek notation.
(The answer to this problem is non-unique)
3. For tax purposes, the Greeks often approximated the area of a quadrilateral field by multiplying
the averages of the two pairs of opposite sides. In one example, the two pairs of opposite sides
were given as
a =
1
4
+
1
8
+
1
16
+
1
32
opposite c =
1
8
+
1
16
, and,
b =
1
2
+
1
4
+
1
8
opposite d = 1
where the lengths are in fractions of of a schonion, a measure of approximately 150 feet. Find the
average of a and c, the average of b and d, and thus the approximate area of the field in square
schonion. The taxman then rounds the answer up to collect a little more tax!
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3.2 Pre-Euclidean Greek Mathematics
Euclid’s Elements (c. 300 BC) forms a natural break point in Greek mathematics, since much of what
came before was subsumed by it. In this section, we consider the contributions of several pre-
Euclidean mathematicians. There are very few sources for Greek mathematics & philosophy before
400 BC, so almost everything is inferred from the writings and commentaries of others.
8
Thales of Miletus (c. 624–546 BC) One of the first people known to state abstract general principles,
Thales was a trader based in Miletus, a city-state in Anatolia. He travelled widely and was likely
exposed to mathematical ideas from all round the Mediterranean. Here are some statements at least
partly attributed to Thales:
The angles at the base of an isosceles triangle are equal.
Any circle is bisected by its diameter.
A triangle inscribed in a semi-circle is right-angled (still known as Thales’ Theorem).
Thales’ major development is generality: his propositions concern all triangles,
circles, etc. The Babylonians/Egyptians observed such results in examples, but
we have little indication that they believed these could be discerned by pure
reason. Thales’ reasoning was almost certainly visual. As an example of typical
geometric reasoning of the period, by 425 BC Socrates could describe how to
halve/double the area of a square by joining the midpoints of edges.
Pythagoras of Samos (c. 572–497 BC) Like Thales, Pythagoras travelled widely, eventually settling
in Croton (southeast Italy) where he founded a school lasting 100 years after his death. It is believed
that Plato learned much of his mathematics from a Pythagorean named Archytas.
The Pythagoreans practiced a mini-religion with ideas out of the mainstream of Greek society.
9
One
of their mottos, “All is number,” emphasised their belief in the centrality of pattern and proportion.
The following quote
10
gives some flavor of the Pythagorean way of life.
After a testing period and after rigorous selection, the initiates of this order were allowed
to hear the voice of the Master [Pythagoras] behind a curtain; but only after some years,
when their souls had been further purified by music and by living in purity in accordance
with the regulations, were they allowed to see him. This purification and the initiation
into the mysteries of harmony and of numbers would enable the soul to approach [be-
come] the Divine and thus escape the circular chain of re-births.
The Pythagoreans were particularly interested in musical harmony and the relationship of such to
number. For instance, they related intervals in music to the ratios of lengths of vibrating strings:
Identical strings whose lengths are in the ratio 2:1 vibrate an octave apart.
A perfect fifth corresponds to the ratio 3:2.
A perfect fourth corresponds to the ratio 4:3.
The use of these intervals to tune musical instruments is still known as Pythagorean tuning.
8
For instance, most of our knowledge of Socrates comes from the voluminous writings of Plato and Aristotle. The
earliest known Greek textbook/compilation (Elements of Geometry) was written around 430 BC by Hippocrates of Chios; no
copy survives, though most of its material probably made it into Book I of Euclid.
9
They were vegetarians, believed in the transmigration of souls, and accepted women as students; controversial indeed!
10
Van der Waerden, Science Awakening pp 92–93
18
Theorems 21–34 in Book IX of Euclid’s Elements are Pythagorean in origin. For instance:
Theorem. (IX .21) A sum of even numbers is even.
(IX .27) Odd less odd is even.
The Pythagoreans also studied perfect numbers, those which equal the sum of their proper divisors
(e.g. 6 = 1 + 2 + 3), and they seem to have observed the following.
Theorem (IX. 36). If 2
n
1 is prime then 2
n1
(2
n
1) is perfect.
They moreover considered square and triangular numbers (
1
2
m( m + 1)) and tried to express geomet-
ric shapes as numbers, in service of their belief that all matter could be formed from basic shapes.
Incommensurability and Pythagoras’ Theorem As with other ancient cultures, the only numbers
in Greek mathematics were positive integers. These were used to compare lengths/sizes of objects.
Definition. Lengths are in the ratio m : n if some sub-length divides exactly m
times into the first and n times into the second.
Lengths are commensurable if some sub-length divides exactly into both.
Ratio 3 : 2
While modern mathematics has no problem with irrational ratios (e.g., the diagonal of a square to its
side is
2 : 1), this conflicted with the core Pythagorean belief that any two lengths were commensurable.
Identifying lengths with real numbers, this belief may be restated in modern language:
m, n R
+
, R
+
, a, b N, such that m = a and n = b
This is complete nonsense for it insists that every ratio of real numbers
m
n
=
a
b
must be rational!
The Pythagorean commensurability supposition stems from their basic tenets: all is number (lengths
represented numerically) and that the design of the gods be perfect (numbers are integers). The
discovery of incommensurable ratios produced something of a crisis; a possibly apocryphal story
states that a disciple named Hippasus (c. 500 BC) was set adrift at sea as punishment for its revelation.
By 340 BC, however, the Greeks were happy to state that incommensurable lengths exist.
Theorem (Aristotle). If the diagonal and side of a square are commensurable, then odd numbers
equal even numbers.
Inferred proof. In Socrates’ doubled-square, suppose that side : diagonal = a : b; these are integers!
Assume at least one of a or b is odd, else the common sub-length may be doubled.
The larger square is twice the smaller, whence the square numbers have ratio
b
2
: a
2
= 2 : 1
It follows that b
2
is even and thus divisible by 4, whence a
2
is also even, and both
a, b are even. Whichever of a, b was odd is also even: contradiction!
b
a a
Note the similarity of this argument to the modern proof of the irrationality of
2.
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While there is no evidence that the Pythagoreans ever provided a correct proof of their famous The-
orem, one argument possibly attributable to them used the idea of commensurability.
‘Proof of Pythagoras’ Theorem. Label the right triangle a, b, c where c
is the hypotenuse and drop the altitude to the hypotenuse. Let d be
the length shown. Similar triangles tell us that
a : d = c : a = a
2
: ad = cd : ad = a
2
= cd
Thus the square on a has the same area as the rectangle below the
d-side of the hypotenuse. Repeat the calculation on the other side
to obtain b
2
= c(c d), and sum to complete the proof.
Since the only numbers were integers, the symbols a, b, c, d are in-
teger multiples of an assumed common sub-length. This restriction
completely destroys the generality of the argument.
a
b
c
d
The organization of Book I of the Elements make clear that its primary goal was to provide a rigorous
proof of Pythagoras’ Theorem which did not depend on the flawed notion of commensurability. With
our modern understanding of real numbers and continuity, there is nothing wrong with the above.
Theaetetus of Athens (417–369 BC) Theaetetus is likely the source for much of the most difficult
part (Books VII & X) of the Elements. His essential definition of (in)commensurability comes from
applying what is now known as the Euclidean algorithm to line segments.
Definition. Let a > b be lengths/segments
11
(a is longer than b). Repeatedly the division algorithm:
a = q
1
b + r
1
r
1
< b (q
1
N
0
and a length r
1
< b)
b = q
2
r
1
+ r
2
r
2
< r
1
r
1
= q
3
r
2
+ r
3
r
3
< r
2
We say that a and b are commensurable if the algorithm terminates: some remainder r
n
divides exactly
into r
n1
. Otherwise a and b are incommensurable.
Ratios are equal a : b = c : d precisely when the sequences of quotients in the algorithm are equal.
If a and b are commensurable, then r
n
is their greatest common sub-length. If we write a = ar
n
and
b = br
n
for integers a, b, and rewrite the algorithm in the modern fashion, the result is the standard
Euclidean algorithm computation of gcd(a, b) = 1.
Example 1 37 : 13 = 148 : 52 since we obtain the same sequence of quotients (2, 1, 5, 2):
37 = 2 ·13 + 11 148 = 2 ·52 + 44
13 = 1 ·11 + 2 52 = 1 ·44 + 8
11 = 5 ·2 + 1 44 = 5 ·8 + 4
2 = 2 ·1 8 = 2 ·4
11
Only the quotients q
k
need be integers, everything underlined is a segment.
20
Example 2 We sketch a proof that the side AB and diagonal AC of a regular pentagon ABCDE are
incommensurable.
1. Prove that BAG is isosceles (GFK =
3
5
·180° = 108°. . . ).
2. Take a =
|
AC
|
and b =
|
AB
|
=
|
AG
|
. The first line of the
algorithm now reads
|
AC
|
=
|
AG
|
+
|
GC
|
=
|
AB
|
+
|
GC
|
so we write a = q
1
b + r
1
where r
1
=
|
GC
|
and q
1
= 1.
3. Since
|
GC
|
=
|
AF
|
, the second line of the algorithm reads
|
AG
|
=
|
AF
|
+
|
FG
|
=
|
GC
|
+
|
FG
|
so that we again have a quotient of q
2
= 1.
A
B
C
D
E
F
G
H
J
K
4. Appealing to congruent isosceles triangles DCG
=
EHF we see that
|
GC
|
=
|
FH
|
is the
diagonal of the interior regular pentagon. The third line of the algorithm is therefore the same
as the first: we are back to considering the ratio of the diagonal to the side of a regular pentagon.
The algorithm therefore continues forever with all quotients being 1.
Example 3 In modern language, the diagonal to the side of a square is the incommensurable ratio
2 : 1. We apply Theaetetus’ algorithm:
2 = 1 ·1 + (
2 1)
1 = 2 ·(
2 1) + (3 2
2)
Observe that 3 2
2 = (
2 1)
2
, whence the second line reads 1 = 2x + x
2
. The following lines in
the algorithm may therefore be obtained by repeatedly multiplying by x:
x = 2x
2
+ x
3
, x
2
= 2x
3
+ x
4
, etc.,
resulting in a never-ending sequence
12
of quotients: 1, 2, 2, 2, 2, 2, . . .
Eudoxus of Knidos (c. 390–337 BC) Eudoxus was arguably the most prolific of the pre-Euclidean
mathematicians. Apart from attending and perhaps teaching at Plato’s academy, he is famous for
explaining how to calculate with ratios of lengths (segments). For example:
Definition. A : B > C : D if there exist positive integers m, n such that mA > nB and mC nD.
At first glance it appears as if Eudoxus is telling us how to compare rational numbers; if A, B, C, D are
integers, we see that
A
B
>
n
m
C
D
which is trivially satisfied by taking m = D and n = C. However, if A, B, C, D were interpreted
as segments rather than integers this is much more useful. Building on the work of Theaetetus, his
mathematics told the Greeks how to approximate incommensurable ratios with rational numbers.
12
If you’re interested in number theory, investigate the relationship of Theaetetus’ algorithm to continued fractions. . .
21
Examples 1. To see that 13 : 3 > 17 : 4, simply choose m = 4 and n = 17 to obtain
4 ·13 = 52 > 51 = 3 ·17
2. We show that the side : diagonal of a square is greater than 1 : 2;
equivalently, the diagonal is less than twice the side.
See the picture, where the side : diagonal = A : B. Choosing
m = D = 2 and n = C = 1, we see that
mA = 2A > B = nB (diag > side of large square)
In modern language, this is merely
1
2
>
1
2
.
A
A
B
Zeno of Elea (c. 450 BC) While not strictly a mathematician, Zeno’s arguments have become essen-
tial parts of the discussion of the infinite and the infinitesimal. These provided fodder for philoso-
phers for thousands of years and lie at the heart of the controversy surrounding the development of
calculus. Here are two of the most famous:
Achilles and Tortoise Achilles chases a Tortoise. After time t
0
, Achilles reaches the Tortoise’s starting
position, but the Tortoise has moved on. After another time t
1
, Achilles reaches the Tortoise’s
second position; again the Tortoise has moved. In this manner Achilles spends t
0
+ t
1
+ t
2
+ ···
in the chase. Zeno’s paradoxical conclusion is that Achilles never catches the Tortoise.
The resolution is that the total duration can be finite, even though it be split into infinitely many
subintervals of time; this idea is at the heart of the modern notion of infinite series.
Arrow paradox An arrow is shot from a bow. At any given instant the arrow doesn’t move. If time is
made up of instants, then the arrow never moves.
This time Zeno debates the the idea that a finite time period can be considered as a sum of
infinitesimal instants. The modern resolution involves the integral.
Constructions and Geometry By the middle of the 5
th
century BC, Greek mathematicians were
solving geometric problems using ruler-and-compass (peg-and-cord) constructions. This approach
perhaps came to Greece from India, or could have arisen organically. Constructions were based on
three rules, which became the first three postulates (axioms) of Book I of Euclid’s Elements.
1. One may join two given points by with straight line segment.
2. Any segment may be extended indefinitely.
3. Given a center and radius, one may draw a circle.
Theorems were often stated as problems: e.g., to bisect a given angle. A proof provided first a construc-
tion, then an argument justifying that the construction really had solved the problem.
By the time of Euclid, the Greeks knew how to construct an equilateral triangle, a square and a regular
pentagon in a given circle: here is a construction of a pentagon.
13
13
Theorem IV. 11 of the Elements presents a less practical construction. Ours follows from Theorem XIII. 10: if a regular
pentagon, hexagon and decagon are inscribed in a circle, then their sides form a right-triangle.
22
1. Draw perpendicular diameters AB and CD and bisect OA at M.
2. Draw an arc centered at M with radius
|
CM
|
. Let N be the in-
tersection of this arc with OB.
3. Draw an arc centered at C with radius
|
CN
|
. Let R be the inter-
section of this arc with the original circle.
4. Move
|
CR
|
around the circle to create a regular pentagon.
O
A
B
C
D
MN
R
A purely geometric proof of the validity of this construction is too difficult for us, but you can easily
check it using a calculator, Pythagoras’ and the cosine rule: if the circle has radius 2, then
|
CR
|
2
=
|
CN
|
2
=
|
ON
|
2
+
|
OC
|
2
= (
5 1)
2
+ 2
2
= 10 2
5 = 2
2
+ 2
2
2 ·2 ·2 cos 72°
Construction problems have motivated mathematicians ever since. In 1796, Gauss (then 19) con-
structed a regular 17-gon. A classification of constructable regular polygons took until 1837.
Theorem. A regular n-gon is constructable if and only if n = 2
k
F
1
···F
r
where F
1
, . . . , F
r
are distinct
primes of the form 2
(2
n
)
+ 1.
After the 17-gon, the next prime-sided constructable n-gon has 257 = 2
2
3
+ 1 sides!
By 400 BC, the Greeks were referencing the second and third impossible constructions of antiquity:
1. Trisecting a general angle.
2. Doubling (the volume of) a given cube.
3. Squaring a circle (construct a square with the same area as a given circle).
14
It wasn’t until the advent of field theory in the 1800s that these were indeed proved to be impossible
using ruler-and-compass constructions.
Summary
Several of the mathematical techniques in this section are difficult, and the results are technical. With
practice, all should be accessible. It isn’t important to become proficient with all of these ideas!
Instead, by playing with them, you should develop an appreciation of two overarching points:
1. Even before Euclid, the focus of Greek mathematics was more abstract and less practical than
other ancient cultures (e.g., the Egyptians, Babylonians & Chinese), in large part due to the
influence of wider Greek philosophy and religion. The modern liberal arts ideal of learning
for its own sake—to celebrate the beauty of knowledge and to expand the mind—is, to a large
extent, a Greek inheritance.
2. By investigating mathematics abstractly, the ancient Greeks were already pondering funda-
mental mathematical questions and concepts, for instance: the relationship between number
and length, continuity, irrationality, infinitesimals & constructability. Such ideas have stimu-
lated mathematical research ever since. Indeed these particular issues would not rigorously be
resolved until the development of modern analysis and algebra in the 1800s by luminaries such
as Gauss, Cauchy and Riemann.
14
“You can’t square that circle” is now a metaphor for something that can’t be done.
23
Exercises 3.2. 1. Construct five Pythagorean triples using the formula
n,
n
2
1
2
,
n
2
+1
2
where n is
odd. Construct five more using the formula
m,
m
2
2
1,
m
2
2
+ 1
where m is even.
2. Suppose 2
n
1 = p is prime (its only positive divisors are itself and 1). List the positive divisors
of 2
n1
(2
n
1) and hence prove Theorem IX. 36.
3. Draw a picture with dots to show that eight times any triangular number plus 1 makes a square,
and that any odd square diminished by 1 becomes eight times a triangular number. That is:
(a) 8 ·
1
2
m( m + 1) + 1 is a perfect square.
(b) If n is odd, then n
2
1 = 8 ·
1
2
m( m + 1) for some m.
4. Find a construction (using the ruler-and-compass constructions) to bisect a given angle, and show
that it is correct.
5. Sketch a construction inscribing a regular hexagon in a circle.
(Assume you can construct an equilateral triangle on a given segment—Thm I. 1 of Euclid, pg. 27)
6. (A line-doubling paradox) One line has twice the length of another and so has more points.
However, there is a bijective correspondence between the points on these lines; the two lines
therefore have the same number of points.
Explain the second observation. How can you resolve the paradox?
7. The cycle of fifths is a musical concept stating that twelve perfect fifths equals seven octaves
(pg. 18). State this claim numerically, and show that it is a contradiction.
(Hint: two strings are seven octaves apart if their lengths are in the ratio 2
7
: 1)
8. We use modern language to resolve Zeno’s paradox of Achilles and the Tortoise. Suppose
Achilles travels at speed v
A
, the tortoise at speed v
B
< v
A
, and that the tortoise starts a distance
d ahead of Achilles.
(a) Prove that t
n
=
d
v
A
v
T
v
A
n
for each positive integer n.
(b) Compute
n=0
t
n
using the geometric series formula from calculus.
(c) Verify the time-value computed in (b) as would a modern Physicist; by considering the
motion of Achilles relative to the tortoise.
9. Use Theaetetus’ definition of equal ratios to prove that 46 : 6 = 23 : 3.
10. (Hard) A line of length 1 is divided at x so that
1
x
=
x
1x
. Prove that 1 and x are incommensu-
rable. Indeed, show that 1 : x is the same as diagonal : side of a regular pentagon.
(Hint: the first line of the algorithm is 1 = x + x
2
. . . )
11. (Hard) Let a > b and c be positive lengths. Use Eudoxus’ definition to prove that c : b > c : a.
(Hint: let n be the smallest integer such that n(a b) c; its existence is the “archimedean property”)
24
3.3 Euclid and the Elements
Euclid worked in the Library of Alexandria, named for the Greek gen-
eral Alexander the Great who conquered Egypt in 323 BC. The Library
was constructed around 320 BC as a means of organizing the knowl-
edge of the world and for the demonstration of Greek power. Al-
though it was seriously damaged on several occasions, the Library re-
mained a center of scholarship until around AD 500. Below is a map of
the city around AD 400: note the size and centrality of the Library.
It is hard to argue against Euclid’s Elements (c. 300 BC) as the most influential mathematics text ever
produced. Likely a compilation of earlier mathematical work rather than a pure original, it was
edited and added to over the centuries, eclipsing and subsuming other works. Particular import
were the edits of Theon of Alexandria (c. AD 400) and his daughter Hypatia, both prolific scholars in
their own right. Due to edits such as these, the precise contents of the original are unknown.
Extant fragments date to around AD 100. The earliest (almost) complete copy is from the the 9
th
century; written in Greek and held at the Vatican, it is missing some of the edits of Theon & Hypatia,
thus demonstrating that multiple versions were in circulation.
Earliest Fragment c. AD 100 Full copy 9
th
C
25
Until the mid 20
th
century, some version of the Elements would have been used as a high-school
textbook in most western and middle-eastern countries. Many editions and variations have been
produced, four of which are shown below:
Latin translation, 1572 High School textbook, 1903
Pop-up edition, 1500s Color edition, 1847
You can download Byrne’s color edition here (very large file!). It is notably different from many
earlier editions: it contains a much longer list of definitions, inserts many more axioms, and relabels
propositions 4 and 5 as axioms (pages xviii–xxiii). The picture on the cover page is Euclid’s proof of
Pythagoras’ Theorem (Book I, Thm. 47).
26
A Brief Overview of the Elements
The Elements consists of thirteen books covering two- and three-dimensional geometry, computa-
tions and number theory. Whether some version of every book was written by Euclid himself is
unknown.
15
The key feature of the Elements is its axiomatic presentation. Each book begins with a list
of axioms/postulates and definitions and proceeds to prove theorems deduced from these. This ax-
iomatic method is essentially universal in modern mathematics, and its advent is fundamentally what
sets Greek mathematics apart from everything that came before.
We briefly discuss Book I, then give some flavor of the remainder of the text with a few example
results. Several examples of material from later books were mentioned in the previous section.
Book I Consists of 48 theorems, culminating with Pythagoras’ and its converse. It seems likely that
Euclid organized Book I with the goal of proving this important result in a rigorous manner: recall
(pg. 20) how the Pythagorean ‘proof relied on the erroneous notion of commensurability. Here are
the postulates from Book I: the first three are what define ruler-and-compass constructions (pg. 22).
P1 Given any two points, a straight line can be drawn between them
P2 Any line may be indefinitely extended
P3 Given a center and a radius, a circle may be drawn
P4 All right angles are equal to each other
P5 If a straight line crosses two others so that the angles on the same side make less than two right
angles, then the two lines meet on that side of the original.
The fifth postulate is awkwardly phrased. An equivalent modern statement is Playfairs axiom:
There is at most one parallel through a given point not on line.
For centuries, mathematicians tried to prove that this postulate was a theorem of the others until; it
was eventually shown to be necessary with the advent of hyperbolic geometry in the 1800s. Euclid’s
refusal to use the parallel postulate until Theorem 29 suggests he understood this awkwardness.
Theorems are generally presented as problems: a pictorial construction is provided, then Euclid proves
that the construction really solves the problem. Here is Euclid’s first theorem.
Theorem (I. 1). Problem: To construct an equilateral triangle on a given segment.
Proof. Given construct two circles (P3)
Join one of the circle intersections to the endpoints of the original segment (P1)
The result is an equilateral triangle; indeed the three sides are congruent, for
are radii of a common circle, as are
15
It is not even certain that Euclid was a single person as opposed to a figurehead or a name for a collective. It is hardly
surprising that we know so little about someone who lived 2300 years ago. The same questions are sometimes raised about
William Shakespeare who lived only 400 years ago!
27
After this Euclid proceeds to establish several well-known results. Since this isn’t a geometry class,
we’ll omit most of the details. You can find more of these here, in Byrne, or elsewhere.
Thm I. 4 Side angle side: if triangles have two pairs of congruent sides and the angles between them
are also congruent, then the remaining sides and angles are congruent.
Thm I. 15 Vertical angles: if two lines meet, then the opposite angles made are congruent.
Thms I. 27 & 29 Angles and parallels: if a line falls on two other lines, then the two lines are parallel
if and only if the alternate angles are congruent (α
=
β in the picture).
α
β
β
δ
γ
α
Thm I. 15 Thms I. 27/29 Thm I. 32 Thm I. 41
Thm I. 32 Angle sums in a triangle: if one side of a triangle is protruded, the exterior angle equals
the sum of the opposite interior angles.
In the picture α + β = δ; in modern language α + β + γ = 180°.
Thm I. 41 A parallelogram and triangle on the same base and with the same height have area in the
ratio 2:1.
The last two results of Book I are Pythagoras and its converse.
Theorem (I. 47). The square on the hypotenuse of a right-triangle has area equal to the sum of the
areas of the squares on the remaining sides.
Proof. Given a right-angle at A, drop the perpendicular from A across
|
BC
|
to L.
FBC and ABFG share the same base BF and height AB.
By Thm I. 41,
area(ABFG) = 2 area(BCF)
Similarly (base BD, height BO)
area(BOLD) = 2 area(ABD)
Side-Angle-Side (Thm I. 4) = ABD
=
FBC; the trian-
gles have the same area, and so
area(ABFG) = area( BOLD)
Similarly area(ACKH) = area(OCEL).
A
B
CO
LD E
F
G
H
K
The converse (Thm I. 48) is Exercise 3.
28
Book II Geometric solutions to problems that would now be treated using algebra. Much of this is
attributable to the Pythagoreans.
(Thm II. 11) A segment may be divided so that the rectangle contained by the whole and one
of the sub-segments is equal to the square on the remaining sub-segment.
We rephrase this in modern language. Suppose the given segment AB has length a, our goal is
to find H on AB such that
|
AH
|
= x and x
2
= a(a x). Euclid is providing a geometric solution
to a quadratic equation!
1. Construct ABDC on AB
2. Let E be the midpoint of AC and connect EB
3. Extend AC and lay off EF
=
EB on AC extended
4. Construct AFGH and drop the perpendicular to I
5. To finish: prove that area(AFGH) = area( BDIH)
The solution x =
|
AH
|
=
51
2
a means that AH : HB is the
golden ratio.
Book III Theorems regarding circles and tangency. Most of this material
likely came from Hippocrates.
(Thm III. 31) Thales’ Thm: a triangle in a semi-circle is right-angled.
Book IV Construction of regular 3, 4, 5, 6 and 15-sided polygons inscribing and exscribing a circle.
Also likely the work of Hippocrates.
Book V Ratios and magnitudes
`
a la Eudoxus.
(Thm V. 11) If a : b = c : d and c : d = e : f then a : b = e : f
Book VI Ratios of magnitudes applied to geometry (similarity results).
(Thm VI. 4) Triangles with equal angles have corresponding sides proportional.
(Thm VI. 8) The altitude from the right angle of a right triangle divides it into two triangles
similar to each other and the the original.
(Thm VI. 31) Corrected Pythagorean proof (pg. 20) of Pythagoras’ using Eudoxus’ proportions
and Thm VI. 8.
Book VII Divisibility and the Euclidean algorithm. Probably due to the Pythagoreans and Theaete-
tus.
Book VIII Number progressions, geometric sequences. Possibly due to studies in music by Archy-
tas (a Pythagorean who taught Plato mathematics).
Book IX Number Theory: even/odd + perfect numbers.
(Thm IX. 20) There are infinitely many primes.
29
Book X Discussion of commensurable and incommensurable ratios. Long and difficult, possibly
derived from Theaetetus.
Book XI Solid geometry (lines/planes in 3D).
(Thm XI. 28) A parallelepiped is bisected by its diagonal plane.
Book XII Ratios of areas and volumes (Eudoxus).
(Thm XII. 2) The areas of circles are in the same ratio as the squares on their diameters.
Book XIII Construction of regular polyhedra inside a sphere and their classification.
(Thm XIII. 10) If a regular pentagon, hexagon and decagon are inscribed in the same circle,
then their sides form a right-triangle.
One could study the Elements and its influence for a lifetime and not be done! Hopefully this very
brief overview convinces you why the book had such a profound impact on mathematics.
Exercises 3.3. 1. Prove Thales’ Theorem (III. 31) (pg. 29).
(Hint: start by joining the center of the circle to the apex of the triangle. . . )
2. Use the picture to provide a proof of Thm I. 32: the sum of the three
interior angles of a triangle is equal to two right angles.
Show that the proof depends on Thm I. 29, and therefore on the
parallel postulate.
(This isn’t quite the same as Euclid’s argument)
β
α
γ
α
3. Suppose that the square on side BC of ABC has the same area
as the sum of the squares on the other sides AB, AC. As in the
picture, draw a perpendicular AD
=
AB.
(a) Explain why DC
=
BC.
(b) Hence conclude that ABC is right-angled at A.
A
B
C
D
4. Prove Thm III. 3: A diameter of a circle bisects a chord if and only if it is perpendicular to the
chord.
5. Verify that Euclid’s construction for Thm II. 11 really does solve the given problem.
(You can use modern algebra!)
6. Draw a semi-circle with diameter 9 + 5 = 14. Solve the equation
9
x
=
x
5
geometrically, by
constructing a vertical line whose length is x.
7. Show that areas of similar segments of circles are proportional to the squares of the length of
their chords.
(You may assume that areas of circles are proportional to the squares on their diameters and can use
modern algebra/trigonometry if you wish)
30
3.4 Archimedes of Syracuse
Archimedes (287–212 BC) is arguably the greatest ancient mathematician. Syracuse is on the island
of Sicily at the foot of the Italian peninsula; at the time of Archimedes’ birth this was a Greek city-
state, though under threat from the expanding Roman Empire. Archimedes famously helped defend
Syracuse against the Romans using catapults, though he ultimately died at their hands after the city
fell. He is believed to have travelled to Alexandria in his youth and perhaps studied with scholars at
the library, including Eratosthenes (pg. 34).
Archimedes’ genius was practical not just mathematical. Beyond his anti-Roman catapults, he is
credited with a large number of inventions and technical innovations, including Archimedes’ screw,
still used in modern irrigation systems to elevate water. He is acknowledged as the founder of hydro-
statics, where Archimedes’ principle states that an object immersed in water loses weight equal to that
of the displaced water. A famous story recounts Archimedes using this to detect whether a smith
had used all the gold he had been given in the manufacture of a crown.
Example A cube with side length 20 cm floats such that the water-
line is halfway up the cube. By Archimedes’ principle, the weight of
the cube is the same as that of the volume of displaced water:
20 ×20 ×10 = 4000 cm
3
which has a weight (mass) of roughly 4 kg.
20 cm
Levers Archimedes made great study of levers, both for practical purposes and as a method of
calculation.
r
1
r
2
M
1
M
2
Given masses M
1
, M
2
located distances r
1
, r
2
from a pivot, Archimedes states:
The lever balances M
1
: M
2
= r
2
: r
1
The lever rotates clockwise M
1
: M
2
< r
2
: r
1
The lever rotates counter-clockwise M
1
: M
2
> r
2
: r
1
In modern terms we’d compare the torques τ
1
= M
1
r
1
and τ
2
= M
2
r
2
. Since torque requires the
multiplication of non-numerical quantities, Archimedes would instead have considered this using
Eudoxus’ theory of proportions.
For example, to find the mass M
2
required to balance a lever given M
1
= 12 lb, r
1
= 4 ft and r
2
= 3 ft,
Archimedes would have observed that
M
2
: M
1
= 4 : 3 = M
2
= 16 lb
31
The Method: is Archimedes the founder of calculus? A previously unknown work of Archimedes
was discovered in 1899. As an amazing application of the lever principle, Archimedes makes an ar-
gument that looks remarkably like modern calculus; he could be claimed to be its earliest practitioner
by 1800 years! The method was outlined in a letter to Eratosthenes and includes part of an argument
for proving Archimedes’ favorite theorem, a picture of this result was engraved on his tomb.
Theorem. A cone, hemisphere and cylinder with the same base and height have volumes in the
ratio 1 : 2 : 3. Using modern formulæ, if the height is r, then the volumes are
1
3
πr
3
:
2
3
πr
3
: πr
3
.
Here is a modernized version of half the result. Suppose the ‘base’ is
a disk with radius 1. Archimedes removes the hemisphere from the
cylinder and places the cone beneath. Compare the cross-sections
the same distance y from the apex of the cone.
The circular cross-section of the cone has radius y whence its
area is proportional to the square on the radius: πy
2
.
The upper annular cross-section has area proportional to the
difference of the squares on the radius of the cylinder and on
the distance x. By Pythagoras’ the cross-sectional area is
π(1
2
x
2
) = π(1 (1 y
2
)) = πy
2
y
y
1
x
The cross-sections are therefore in balance with respect to a vertical lever whose pivot lies at the
center of the picture. Archimedes concludes that the cone and the upper-figure are in balance: that is
V
cone
= V
cylinder
V
hemisphere
in line with the desired ratios.
Here is another argument of Archimedes’ with a suggestion of calculus. A disk comprises infinitely
many concentric circles, the circumference of each being proportional to its radius. ‘Unwind’ these
circles to obtain a triangle; one side is the radius of the disk, the other its circumference. The area of
a circle is therefore that of a triangle with sides the radius and circumference of the circle: A =
1
2
rc.
c
r
The Method includes several of these calculus-like discussions. While efficient, Archimedes felt that
his approach didn’t constitute a proof and provided alternative arguments elsewhere in his writings.
The essential problem is this;
Can we really say that an area equals its cross-sectional lines? Or that a volume equals its
cross-sectional areas? Lines have no width so if we add them up we have no area. If they
have width, then infinitely many of them have infinite area.
These are really variations of Zeno’s paradoxes (pg. 22) regarding infinitesimals and indivisibles!
32
Archimedes’ arguments would be resurrected in the early 1600s by Cavalieri and Galileo as the de-
velopment of calculus gathered pace. The same duality of presentation characterised this later devel-
opment: Newton and others found the infinitesimal approach efficient, but felt the need to present
geometric proofs to convince readers that their results weren’t mere trickery.
It is tempting to imagine what might have happened if Archimedes’ method had been accepted and
preserved as part of the Greek canon; if calculus had been developed 1800 years earlier, how might
this have affected technological development? Would the space-race have happened in AD 500?!
Quadratures Archimedes also approximated areas and arc-lengths of various figures using limit-
like argumentation. Here is how he approached the area/circumference of a circle.
1. Inscribe a regular hexagon in a circle (of radius 1 say) and compute its perimeter (6).
2. Halve each angle to obtain a regular dodecagon: compute its perimeter (12
p
2
3).
3. Repeat the angle-halving process: Archimedes did this with 24-, 48- and 96-gons to obtain an
increasing sequence of perimeters bounded above by the circumference of the circle (2π).
4. Repeat the same calculation with circumscribed polygons to obtain a decreasing sequence of
over-estimates.
5. Using 96-sided polygons allowed Archimedes to obtain the estimate 3
10
71
< π < 3
1
7
.
Archimedes’ halving process relied on an induction step, an ap-
proximation of which we mimic here. Suppose we have an
isosceles triangle with equal legs 1, altitude d
n
, and chord 2h
n
.
We halve the angle to find the new altitude d
n+1
and chord 2h
n+1
.
Everything follows from three applications of Pythagoras’:
1 = d
2
n
+ h
2
n
(2h
n+1
)
2
= h
n
2
+ (1 d
n
)
2
1 = d
2
n+1
+ h
2
n+1
Expanding and cancelling, we obtain
d
2
n+1
=
1
2
(1 + d
n
), h
2
n+1
= 1 d
2
n+1
=
1
2
(1 d
n
)
1
1
d
n
h
n
h
n
d
n+1
h
n+1
h
n+1
1 d
n
Since d
0
=
3
2
and h
0
=
1
2
, we may compute the entirety of both sequences:
d
1
=
1
2
q
2 +
3, d
2
=
1
2
r
2 +
q
2 +
3, . . . d
n
=
1
2
s
2 +
r
2 + ··· +
q
2 +
3
h
1
=
1
2
q
2
3, h
2
=
1
2
r
2
q
2 +
3, . . . h
n
=
1
2
s
2
r
2 + ··· +
q
2 +
3
where the n
th
terms have n copies of the digit 2 under the square-root. The circumference and area
of the 6 ·2
n
-sided polygon inscribed in the circle are therefore
C
n
= 12 ·2
n
h
n
, A
n
= 6 ·2
n
d
n
h
n
= 6 ·2
n1
h
n1
=
1
2
C
n1
33
These sequences increase to 2π and π respectively. For a 96-sided polygon, Archimedes would have
had to approximate
C
4
= 12 ·2
4
h
4
= 96
v
u
u
t
2
s
2 +
r
2 +
q
2 +
3 > 6.282 = π > 3.141 > 3
10
71
Other Highlights of the later Greek Period: 300 BCAD 500
We’ll consider ancient astronomy, including Greek contributions, in the next chapter. Here are a few
of the other developments of the late Greek period and some historical context.
Eratosthenes (276–194 BC) grew up in Cyrene (c. 500 miles west of Alexandria in modern-day
Libya) and moved to Alexandria in adulthood to become its librarian. He is credited with a
simple algorithm for finding primes: the Sieve of Eratosthenes.
List the integers n 2.
Leave 2 and delete all its multiples.
Leave 3 and delete its multiples.
Repeat ad infinitum: each time one reaches a number, leave it and delete its multiples.
The remaining list contains all the primes.
Apollonius (225 BC) writes an eight-volume book on conic sections building on earlier work of
Menaechmusus (350 BC).
By 146 BC the Greek empire had fallen under Roman rule. Alexandria remained important.
Educated Greeks still spoke and wrote in Greek rather than (Roman) Latin. For context, Julius
Caesar ruled Rome around this time (died 44 BC).
Heron (AD 75) proves the formula
p
s( s a)(s b)(s c) for the area of triangle, where s =
1
2
(a + b + c) is the semi-perimeter. This was likely known to Archimedes; Heron’s work was a
compilation of earlier mathematics.
Around AD 100 the Neopythagorean’s worked in Alexandria, studying music, philosophy, and
number, with the intent of reviving the teachings of Pythagoras.
Around AD 400, Theon and Hypatia produce the most widely-read edition of Euclid’s Elements
as well as improving upon several earlier mathematical topics.
In AD 395 the Roman empire split into eastern and western parts centered on Rome and Byzan-
tium/Constantinople. The western empire rapidly declined under the pressures of corruption
and barbarian attacks, collapsing completely by AD 500. Alexandria experienced riots and a
bloody power-struggle (Hypatia was murdered by a mob in 415) and the library of Alexandria
was severely damaged and possibly destroyed at this time. In 642, Alexandria was captured
by the new Islamic caliphate. Much of the material in the library survived by being copied and
transported to various places of learning; particularly Constantinople and Baghdad. For the
next 600 years, the knowledge of Alexandria was largely a mystery to (western) Europe.
34
Exercises 3.4. 1. If a weight of 8 kg is placed 10 m from the pivot of a lever and a weight of 12 kg is
placed 8 m from the pivot in the opposite direction, toward which weight will the lever incline?
Answer using Archimedes’ language.
2. Use Eratosthenes’ Sieve to find all the primes < 100.
3. (a) Prove Heron’s formula as follows.
i. Let h be the altitude and x the base of the left-hand right-
triangle. Apply Pythagoras’ to the two right-triangles to
show that
x =
a
2
+ b
2
c
2
2a
a
b
c
h
x
ii. Substitute in h
2
= b
2
x
2
to find h in terms of a, b, c and thus deduce Heron’s formula.
(b) Find the area of a triangle with sides 4, 7 and 10.
4. Suppose C
n
is the circumference of a 6 ·2
n
-sided inscribed polygon in a unit circle. Show that
the circumference of the corresponding circumscribed polygon is C
ex
n
=
1
d
n
C
n
.
5. Use the modern formula A =
1
2
ab sin C to prove that, for any k N
1
2
k sin
2π
k
< π < k tan
π
k
Moreover, explain why both sides converge to π.
6. Instead of modern algebra, Archimedes used several geometric lemmas to help find the areas
of polygons inscribed in and circumscribing circles. Here is one; prove it!
Let OA be the radius of a circle and AC be tangent to the circle at A. Let D lie on AC such that
OD bisects COA. Then
|
DA
|
|
OA
|
=
|
CA
|
|
CO
|
+
|
OA
|
and
|
DO
|
2
=
|
OA
|
2
+
|
DA
|
2
(Hint: draw a picture and let T be the intersection of the circle and OC)
7. (Hard) Archimedes used a geometric series approach to evaluate the area inside a parabola.
Use modern algebra for this question.
(a) Suppose y = a + bx + cx
2
is the equation of a
parabola. If P, Q, R have x co-ordinates in an arith-
metic sequence x ϵ, x, x + ϵ, show that the area of
PQR is A =
|
c
|
ϵ
3
; independent of x!
(b) With reference to the picture, if A is the area of the
large triangle, explain why the smaller triangle has
area A
1
=
1
8
A.
(c) Use a geometric series to prove that the area inside
the parabola bounded by PR is
4
3
A
x
A
A
1
P
Q
R
35