WEEK 6
M: Midterm
W: Proof of Proposition I.2.6(b). Theory towards the proving that
\in is a linear ordering
on \omega.
I.2.7. Proposition. The relation \in is irreflexive
on \omega
Corollary. \in is a
strict partial ordering on \omega
Definition. A strict
partial ordering R is linear on A if and only if for all
elements x,y from A we have:
x R y or
x = y or y R x.
I.2 8. Proposition. \in is a strict linear ordering
on \omega (The proof will come later.)
I.2.9. Lemma. For every x,y from \omega we have the
following:
If S x \in y then either S(x)\in y or S(x) = y
PROBLEMS FOR DISCUSSIONS:
1. Show that for every x from \omega we have: either
O \in x or else O = x; here O is
the empty set.
2. Assume A is a nonempty subset of \omega such that
the union of A is equal to A. Show
that A = \omega. (Hint: Show that A is inductive.
Apply the fact that every element
of \omega is a transitive set.)
3. Let B = {O, S(O)} where O is the empty set.
(Thus, taking into account our
representation of natural numbers, B = {0,1}.)
Notice that B = S(S(O)). By
Exercise 2(c) from W, Week 5, the power set
of B (briefly P(B)) is transitive.
However, P(B) contains sets that are not transitive
-- try to find some.
F: Completion of the proof of Proposition I.2.9. Proof of Proposition
I.2.8. Well-orderings.
I.2.10. Definition. A strict linear ordering R on a
set A is a well-ordering if and only
if every nonempty
subset of A has an R-least element. (An R-least element of
B is an element a
\in B such that a R b whenever b is in B and is distict from a.)
I.2.11. Proposition. The relation \in is a well-ordering
on \omega.
PROBLEMS FOR DISCUSSIONS:
1. Show that the definition of a well-ordering makes
also sense for for linear orderings
that are not strict; try to understand where
the difference is and that it is not relevant.
In future, we will only consider strict well-ordering,
unless explicitly stated otherwise.
2. Assume that R is a partial ordering (strict or non-strict;
this is not relevant) on the
set A, and that R has the following property:
If B is a nonempty subset of A then B
has an R-least element (in the sense explained
in Definition I.2 10). Show that R is
a well-ordering on A. (Note: this involves showing
that R is a linear ordering.)
3. Assume that R is a well-ordering on a set A and that
A' is a subset of A. Show that
R is a well-ordering on A'. (More precisely,
we have to view R as a binary relation
on A', so strictly speaking we should consider
the intersection of R with A' x A' instead
of R.)
4. Let R be a well-ordering on a set A, let a
be some object that is not an element
of A, and let A' be the union of A with {a}.
(So A' is obtained by adding a to A.) Define
a binary relation R' on A' as follows:
-- R' agrees with R on A, i.e. for x,y \in A
we have x R y if and only if x R' y
-- If x \in A then x R' a
-- NOT a R' a
Show that R' is a strict linear ordering on A';
in this case R' is called
an end-extension of R (Try to understand
why.)
Show that R' is a well-ordering on A'.
5. (a) Assume x \in \omega. Show that \in is a well-ordering
on x
(b) Show that \in is a well-ordering on S(\omega),
S(S(\omega)), ...
(c) In general show: If x is a transitive set
and \in is a well-ordering on x then S(x) is
also a transitive set and
\in is a well-ordering on S(x).